F(x)=3x^2+7x+3

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Solution for F(x)=3x^2+7x+3 equation: 



(F)=3F^2+7F+3

We move all terms to the left:

(F)-(3F^2+7F+3)=0

We get rid of parentheses

-3F^2+F-7F-3=0

We add all the numbers together, and all the variables

-3F^2-6F-3=0

a = -3; b = -6; c = -3;
Δ = b2-4ac
Δ = -62-4·(-3)·(-3)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$F=\frac{-b}{2a}=\frac{6}{-6}=-1$

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